aaaa abab
4 3
思路:这里讲得很详细了http://blog.csdn.net/ggggiqnypgjg/article/details/6645824
#include <cstdio>
using namespace std;
char s[110005],str[220010];
int p[220010];
int main()
{
int len,i,maxlen,maxindex,ans;
while(~scanf("%s",s))
{
str[0]=‘$‘;
str[1]=‘#‘;
for(i=0;s[i];i++)
{
str[i*2+2]=s[i];
str[i*2+3]=‘#‘;
}
len=i*2+2;
str[len]=‘\0‘;
maxlen=0;
for(i=1;i<len;i++)
{
if(maxlen>i) p[i]=p[2*maxindex-i]<maxlen-i?p[2*maxindex-i]:maxlen-i;
else p[i]=1;
while(str[i-p[i]]==str[i+p[i]])
{
p[i]++;
}
if(p[i]+i>maxlen)
{
maxlen=p[i]+i;
maxindex=i;
}
}
ans=0;
for(i=1;i<len;i++) if(ans<p[i]) ans=p[i];
printf("%d\n",ans-1);
}
}
HDU-3068-最长回文 (Manacher算法),码迷,mamicode.com
原文地址:http://blog.csdn.net/faithdmc/article/details/24658273