标签:
3 3 21 25
None 11 5
zhuyuanchen520 | We have carefully selected several similar problems for you: 4390 4398 4397 4395 4393
ac代码
#include<stdio.h>
#include<string.h>
#define INF 1<<30
#define max(a,b) (a>b?a:b)
#define min(a,b) (a>b?b:a)
int a[20];
__int64 mod[20],ans,n,len;
void init()
{
mod[0]=1;
for(int i=1;i<20;i++)
{
mod[i]=mod[i-1]*10;
}
}
void fun()
{
__int64 temp=n;
len=0;
memset(a,0,sizeof(a));
while(temp)
{
a[len++]=temp%10;
temp/=10;
}
}
void dfs(int now,int step)
{
if(step==len)
{
ans=min(ans,now);
return;
}
for(int i=0;i<=9;i++)
{
__int64 to,temp=now+mod[step]*i;
to=temp;
temp*=temp;
temp/=mod[step];
temp%=10;
if(temp==a[step])
{
dfs(to,step+1);
}
}
}
int main()
{
int t;
init();
scanf("%d",&t);
while(t--)
{
scanf("%I64d",&n);
fun();
ans=INF;
dfs(0,0);
if(ans==INF)
{
printf("None\n");
}
else
printf("%d\n",ans);
}
}HDOJ 题目4394 Digital Square(DFS)
标签:
原文地址:http://blog.csdn.net/yu_ch_sh/article/details/44890631