[LeetCode]Plus One

标签：leetcode

</pre>简单题不解释, 维护一个进位即可<pre name="code" class="java">public class Solution {
  public int[] plusOne(int[] digits) {
      
      int c = 1;
      for(int i = digits.length - 1; i >=0; i --){
          if(c == 0)break;
          digits[i] += c;
          if(digits[i] > 9){
              c = 1;
              digits[i] -= 10;
          }else {
              c = 0;
          }
      }
      
      if (c > 0){
          int [] d = new int[digits.length + 1];
          d[0] = c;
          return d;
      }else 
          return digits;
  }

}

[LeetCode]Plus One

标签：leetcode

原文地址：http://blog.csdn.net/youmengjiuzhuiba/article/details/44902771