Merge Sorted Array--LeetCode

标签：c++   leetcode   算法   

Given two sorted integer arrays A and B, merge B into A as one sorted array.

Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m and n respectively.

思路：如果A的空间够，那么从后往前开始填充即可

void merge(int A[], int m, int B[], int n) 
{
   int i,j=m-1;
   int cur= m+n-1;
   for(i=n-1;i>=0;)
   {
      if(A[j] > B[i])
       A[cur--] = A[j--];
      else
       A[cur--] = B[i--];             
   }     
}

Merge Sorted Array--LeetCode

标签：c++   leetcode   算法   

原文地址：http://blog.csdn.net/yusiguyuan/article/details/45023657