Length of Last Word

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题目描述：

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

题目理解：

求一个只有空格和大小写字母组成的字符串中最后一个单词的大小。

解题思路：

class Solution {
public:
    int lengthOfLastWord(const char *s) {
 	if (strlen(s)==0) return 0;
		string str=s;
		reverse(str.begin(),str.end());
		int flag=0,last_length=0;
		for (string::iterator iter=str.begin();iter!=str.end();iter++)
		{
			if (*iter!=' ')
			{
				last_length++;
				flag=1;
			}
			if (*iter==' '&&flag==1)
			{
				return last_length;
			}
		}
		return last_length;
    }
};

Length of Last Word

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原文地址：http://blog.csdn.net/sinat_24520925/article/details/45071859