编程之美-资格赛-2月29

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简单模拟题

#include <iostream>
#include <string>

using namespace std;

//判断是不是闰年
bool is(int year){
    return year % 400 == 0?true:
        (year % 100 == 0?false:(year % 4 == 0?true:false));
}

//判断结束日期是否不包括2月29
#define NO2 (in2Var1 < 3 && !(in2Var1 == 2 && in2Var2 == "29,"))
//判断开始日期是否包括2月29
#define YES1 (in1Var1 < 3)

int main(void)
{
    int t;
    cin >> t;
    //月份列表
    string str[] = {"January", "February", "March", "April", "May", "June",
     "July", "August", "September", "October", "November" , "December"};
    //输入月份
    string in1Var0,in2Var0;
    //数值月份
    int in1Var1,in2Var1;
    //输入日期
    string in1Var2,in2Var2;
    //输入年份
    int in1Var3,in2Var3;
    for(int i = 1; i <= t; ++i){
        cin >> in1Var0 >> in1Var2 >> in1Var3;
        cin >> in2Var0 >> in2Var2 >> in2Var3;
        int count = 0;
        //月份从字符串换算到数值
        for(int j = 0; j < 12; ++j){
            if(in1Var0 == str[j])
                in1Var1 = j+1;
            if(in2Var0 == str[j])
                in2Var1 = j+1;
        }
        //对闰年的粗糙加减,从开始年份的末尾到结束年份的末尾.
        count += in2Var3/4 - in1Var3/4;
        count -= in2Var3/100 - in1Var3/100;
        count += in2Var3/400 - in1Var3/400;
        //判断开始年份是闰年且开始日期包括2月29
        if(is(in1Var3) && YES1)
            ++count;
        //判断结束年份是闰年且结束日期不包括2月29
        if(is(in2Var3) && NO2)
            --count;
        cout << "Case #" << i << ": " << count << endl;
    }
    return 0;
}

编程之美-资格赛-2月29

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原文地址：http://blog.csdn.net/lane_l/article/details/45117825