斐波拉契数列
#include <stdio.h>
#define NUM 13
int main()
{
int i;
long fib[NUM] = {1,1};
for(i=2 ; i<NUM ;i++)
{
fib[i] = fib[i-1] + fib[i-2];
}
for( i =0 ;i<NUM ; i++)
{
printf("%d月兔子总数:%d\n", i ,fib[i]);
}
getch();
return 0;
}原文地址：http://9815936.blog.51cto.com/9805936/1637359
