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【leetcode】Happy Number

时间:2015-04-27 18:11:45      阅读:154      评论:0      收藏:0      [点我收藏+]

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Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

1^2 + 9^2 = 82
8^2 + 2^2 = 68
6^2 + 8^2 = 100
1^2 + 0^2 + 0^2 = 1

 

 1 class Solution {
 2 public:
 3     int cnt=0;
 4 
 5     int Sum(int m)
 6     {
 7         cnt++;
 8         int sum=0;
 9         int tmp=0;
10         while(m>0)
11         {
12             tmp=m%10;
13             sum=sum+pow(tmp,2);
14             m=m/10;
15         }
16         if(sum==1)
17         {
18             return 1;
19         }
20         if(cnt>=100&&sum!=1)
21         {
22             return 0;
23         }
24         
25         Sum(sum);
26     }
27 
28     bool isHappy(int n) {
29         if(n==0) return false;
30 
31         if(Sum(n)==1) return true;
32         if(Sum(n)==0) return false;
33     }
34 };

 

【leetcode】Happy Number

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原文地址:http://www.cnblogs.com/jawiezhu/p/4460845.html

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