iOS 数组排序实例

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iOS 数组排序 
NSMutableArray *p = [[NSMutableArray alloc] initWithObjects:@"S1",@"S14",@"S3",@"S4",@"S12",@"S6",@"S7",@"S8",@"S9",@"S10",@"S11",@"S5",@"S13",@"S2",nil];
答案：（比比谁的方法简单，高效）

    NSMutableArray *p = [[NSMutableArray alloc] initWithObjects:@"S1",@"S14",@"S3",@"S4",@"S12",@"S6",@"S7",@"S8",@"S9",@"S10",@"S11",@"S5",@"S13",@"S2",nil];
    
    [p sortUsingComparator:^NSComparisonResult(id obj1, id obj2) {
        NSString *a = (NSString *)obj1;
        NSString *b = (NSString *)obj2;
        
        int aNum = [[a substringFromIndex:1] intValue];
        int bNum = [[b substringFromIndex:1] intValue];
        
        if (aNum > bNum) {
            return NSOrderedDescending;
        }
        else if (aNum < bNum){
            return NSOrderedAscending;
        }
        else {
            return NSOrderedSame;
        }
    }];
    
    
    NSLog(@"p %@", p);

iOS 数组排序实例

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原文地址：http://www.cnblogs.com/huangzs/p/4466490.html