标签:acm
const int MAXN = 100001;
vector<int> vt[MAXN];
bool match(int ind, int val)
{
if (ind >= MAXN) return false;
return binary_search(all(vt[ind]), val);
}
int main()
{
// freopen("in.txt", "r", stdin);
int n, a, b, bound;
while (~RI(n))
{
REP(i, MAXN) vt[i].clear();
bound = (int)sqrt(n * 1.0);
REP(i, n)
{
RII(a, b);
vt[a].push_back(b);
}
REP(i, MAXN)
{
sort(all(vt[i]));
}
LL ans = 0;
REP(i, MAXN)
{
if (vt[i].size() > bound)
{
FF(j, i + 1, MAXN)
{
int dis = j - i;
REP(k, vt[j].size())
{
int val = vt[j][k];
if (match(j, val + dis) && match(i, val) && match(i, val + dis))
ans++;
}
}
}
else
{
REP(j, vt[i].size()) FF(k, j + 1, vt[i].size())
{
int dis = vt[i][k] - vt[i][j];
if (match(i + dis, vt[i][k]) && match(i + dis, vt[i][j]))
ans++;
}
}
}
cout << ans << endl;
}
return 0;
}
Codeforces Round #243 (Div. 1)——Sereja and Squares
标签:acm
原文地址:http://blog.csdn.net/wty__/article/details/24743347