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\[PR(\mu ) = \sum\limits_{\nu \in {B_\mu }} {\frac{{PR(\nu )}}{{L(\nu )}}} \]
\[{L(\nu )}\]
\[\mu \]
\[{{B_\mu }}\]
\[R = \left( {\begin{array}{*{20}{c}}{PageRank({p_1})}\\{PageRank({p_2})}\\ \vdots \\{PageRank({p_N})}\end{array}} \right)\]
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原文地址：http://www.cnblogs.com/stemon/p/4497139.html
