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题目：
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
代码：
class Solution { public: void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) { int i1 = m-1, i2 = n-1, i = m+n-1; while ( i1>=0 && i2>=0 ){ if ( nums1[i1]<nums2[i2] ){ nums1[i--] = nums2[i2--]; } else{ nums1[i--] = nums1[i1--]; } } while (i2>=0) nums1[i--] = nums2[i2--]; } };
tips：
双指针，从后往前扫描。
如果最后i1大于等于0则不用处理了；如果最后i2大于等于0，再处理一下。记住。
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原文地址：http://www.cnblogs.com/xbf9xbf/p/4511882.html
