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class Solution:
# @param {integer[]} nums
# @param {integer} target
# @return {integer[]}
def searchRange(self, nums, target):
if target in nums:
result = []
start = nums.index(target)
result.append(start)
times = nums.count(target)
result.append(start+times-1)
return result
else:
return [-1, -1]Leetcode 34 Search for a Range
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原文地址:http://blog.csdn.net/andrew9tech/article/details/45889891