Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
没什么太多讲的,可以使用递归和迭代两种方法来做,要仔细考虑各种输入情况。code如下:
class Solution {
public:
ListNode *deleteDuplicates(ListNode *head) {
if(head == NULL)
return NULL;
ListNode *first = head,*second = NULL,*result = NULL;
bool isDup = false;
while(first!=NULL)
{
isDup = false;
while(first->next != NULL && first->val == first->next->val)
{
isDup = true;
first = first->next;
}
if(!isDup)
{
if(second == NULL)
{
second = first;
if(result == NULL)
result = second;
}
else
{
second->next = first;
second = second->next;
}
}
first = first->next;
}
if(second!=NULL)
second->next = NULL;
return result;
}
};leetcode——Remove Duplicates from Sorted List II 删除排序字符串中重复字符(AC),布布扣,bubuko.com
leetcode——Remove Duplicates from Sorted List II 删除排序字符串中重复字符(AC)
原文地址:http://blog.csdn.net/dalongyes/article/details/30967689