0 1 2 3 4 5
no no yes no no no
代码
#include <iostream>
using namespace std;
int main()
{
long n;
while(cin>>n)
{
if(n>0&&(n-2)%4==0)
cout<<"yes"<<endl;
else
cout<<"no"<<endl;
}
return 0;
}
原文地址:http://blog.csdn.net/blue_skyrim/article/details/46125757