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Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 8339 Accepted Submission(s):
4476
#include<stdio.h>
#include<string.h>
#define minn(a,b)(a<b?a:b)
#define maxm(c,d)(c>d?c:d)
int main()
{
int n,m,j,i,sum,maxx,maxy,minx,miny,x,y;
while(1)
{
sum=0;
minx=250;miny=250;maxx=-250;maxy=-250;//注意对maxx和maxy初值的赋值要大于体中要求的231
while(scanf("%d %d",&x,&y)!=EOF)
{
sum++;
if(sum==1)
{
if(x==0&&y==0)
return 0;
}
if(sum>1)
{
if(x==0&&y==0)
break;
}
if(minx>x)
minx=x;
if(maxx<x)
maxx=x;
if(miny>y)
miny=y;
if(maxy<y)
maxy=y;
}
printf("%d %d %d %d\n",minx,miny,maxx,maxy);
}
return 0;
}
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原文地址:http://www.cnblogs.com/tonghao/p/4548041.html