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[LeetCode] Binary Tree Inorder Traversal

时间:2014-06-28 11:26:55      阅读:206      评论:0      收藏:0      [点我收藏+]

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Given a binary tree, return the inorder traversal of its nodes‘ values.

For example: Given binary tree {1,#,2,3},

   1
         2
    /
   3

 

return [1,3,2].

Note: Recursive solution is trivial, could you do it iteratively?

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector<int> inorderTraversal(TreeNode *root) {
        vector<int> res;
        
        TreeNode *p = root;
        stack<TreeNode*> s;
        while(p!=NULL || !s.empty()){
            
            while(p!=NULL){
                s.push(p);
                p=p->left;
            }//end while
            
            if(!s.empty()){
                p = s.top();
                s.pop();
                res.push_back(p->val) ;//刚开始定义res时,它是空的,则不能使用下标操作,只能有push_back()添加新元素
                p = p->right;   
            }//end while 
        }//end while
        return res;
    }
};

 

[LeetCode] Binary Tree Inorder Traversal,布布扣,bubuko.com

[LeetCode] Binary Tree Inorder Traversal

标签:des   style   blog   color   使用   strong   

原文地址:http://www.cnblogs.com/Xylophone/p/3798925.html

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