Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Assume that the total area is never beyond the maximum possible value of int.

解题思路

面积 = 总面积 - 重叠面积

实现代码

// Runtime: 2 ms
class Solution {
public:
    int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int area = (D - B) * (C - A) + (H - F) * (G - E);
        if (A >= G || B >= H || C <= E || D <= F)
        {
            return area;
        }

        int top = min(D, H);
        int right = min(C, G);
        int bottom = max(B, F);
        int left = max(A, E);

        return area - (top - bottom) * (right - left);
    }
};