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[LeetCode] Invert Binary Tree

时间:2015-06-12 16:58:39      阅读:71      评论:0      收藏:0      [点我收藏+]

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Invert Binary Tree

Invert a binary tree.

     4
   /     2     7
 / \   / 1   3 6   9

to

     4
   /     7     2
 / \   / 9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.

 

额, 这也不能怪Google,既然你这么吊,连这道题都做不出来就真的太不应该了。

(╯°□°)╯︵ ???? ???u?q

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     TreeNode* invertTree(TreeNode* root) {
13         if (root == NULL) return NULL;
14         TreeNode *res = new TreeNode(root->val);
15         res->left = invertTree(root->right);
16         res->right = invertTree(root->left);
17         return res;
18     }
19 };

 

[LeetCode] Invert Binary Tree

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原文地址:http://www.cnblogs.com/easonliu/p/4571909.html

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