标签:uva
题意:
求1~n的二进制中连续出现的两个1有多少个
思路:
首先枚举两个1的位置,如果此时枚举的位置与元素一样,则还要多加
#include <iostream>
#include <stdio.h>
#include <string.h>
#include <string>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <vector>
#include <math.h>
#include <bitset>
#include <list>
#include <algorithm>
#include <climits>
using namespace std;
#define lson 2*i
#define rson 2*i+1
#define LS l,mid,lson
#define RS mid+1,r,rson
#define UP(i,x,y) for(i=x;i<=y;i++)
#define DOWN(i,x,y) for(i=x;i>=y;i--)
#define MEM(a,x) memset(a,x,sizeof(a))
#define W(a) while(a)
#define gcd(a,b) __gcd(a,b)
#define LL long long
#define N 100005
const LL MOD = 1e13;
#define INF 0x3f3f3f3f
#define EXP 1e-8
#define lowbit(x) (x&-x)
LL a,b;
void add(LL x)
{
b+=x;
a+=b/MOD;
b%=MOD;
}
int main()
{
LL cas = 1,n;
while(scanf("%lld",&n),n>=0)
{
LL m = 1,t=n;
a = b = 0;
while(n)
{
add((n>>2)*m);
if((n&3)==3) add((t&(m-1))+1);
m<<=1;
n>>=1;
}
printf("Case %lld: ",cas++);
if(a)
printf("%lld%013lld\n",a,b);
else
printf("%lld\n",b);
}
return 0;
}
标签:uva
原文地址:http://blog.csdn.net/libin56842/article/details/46504035