leetcode 88 Merge Sorted Array

标签：algorithm   c++   leetcode   python   

Given two sorted integer arrays nums1 and nums2, merge nums2 intonums1 as one sorted array.

Note:
You may assume that nums1 has enough space (size that is greater or equal tom + n) to hold additional elements from nums2. The number of elements initialized innums1 and nums2 are m and n respectively.

测试用例：

错误的解决方案：

class Solution {
public:
    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) 
    {
    set<int> result;
    for(int i = 0;i<m;i++)
    {
        result.insert(nums1[i]);
    }
    for(int i = 0;i<n;i++)
    {
        result.insert(nums2[i]);
    }
    nums1.clear();
    set<int>::iterator iter = result.begin();
    for(;iter!=result.end();iter++)
    {
        nums1.push_back(*iter);
    }
    }
};

我的解决方案：上面就是相同 的元素没装进来，换成multiset就行了

class Solution {
public:
    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) 
    {
    multiset<int> result;
    for(int i = 0;i<m;i++)
    {
        result.insert(nums1[i]);
    }
    for(int i = 0;i<n;i++)
    {
        result.insert(nums2[i]);
    }
    nums1.clear();
    set<int>::iterator iter = result.begin();
    for(;iter!=result.end();iter++)
    {
        nums1.push_back(*iter);
    }
    }
};

 简短的解决方案：

class Solution {
public:
    void merge(int A[], int m, int B[], int n) {
        int k = m + n;
        while (k-- > 0)
            A[k] = (n == 0 || (m > 0 && A[m-1] > B[n-1])) ?  A[--m] : B[--n];
    }
};

可读性较好：

class Solution {
public:
    void merge(int A[], int m, int B[], int n) {
        int i=m-1;
        int j=n-1;
        int k = m+n-1;
        while(i >=0 && j>=0)
        {
            if(A[i] > B[j])
                A[k--] = A[i--];
            else
                A[k--] = B[j--];
        }
        while(j>=0)
            A[k--] = B[j--];
    }
};

python解决方案：

class Solution:
# @param A  a list of integers
# @param m  an integer, length of A
# @param B  a list of integers
# @param n  an integer, length of B
# @return nothing(void)
def merge(self, A, m, B, n):
    x=A[0:m]
    y=B[0:n]
    x.extend(y)
    x.sort()
    A[0:m+n]=x

python解决方案2：thats why we love python

def merge(self, A, m, B, n):
        A[m:] = B[:n]
        A.sort()

leetcode 88 Merge Sorted Array

标签：algorithm   c++   leetcode   python   

原文地址：http://blog.csdn.net/wangyaninglm/article/details/46628043