循环-09. 支票面额(15)

 1 #include<iostream>
 2 using namespace std;
 3 int main(){
 4     int n,y,f,flag=1;
 5     cin>>n;
 6     for(y=0;y<100;y++)
 7         for(f=0;f<100;f++)
 8             if((n+2*f+200*y)==(y+100*f)){
 9                 cout<<y<<"."<<f<<endl;
10                 flag=0;
11             }
12     if(flag)
13         cout<<"No Solution"<<endl;
14     return 0;
15 }