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Description：
Given a sorted array of integers, find the starting and ending position of a given target value.
Your algorithm‘s runtime complexity must be in the order of O(log n).
If the target is not found in the array, return [-1, -1].
For example, Given [5, 7, 7, 8, 8, 10] and target value 8, return [3, 4].
public class Solution {
public int[] searchRange(int[] nums, int target) {
int flag = -1, start=-1, end = -1;
for(int i=0; i<nums.length; i++) {
if(nums[i] == target) {
start = i;
for(int j=i; j<nums.length; j++) {
if(nums[j] != target) {
end = j-1;
flag = 1;
break;
}
if(nums[j]==target && j==nums.length-1) {
end = j;
flag = 1;
break;
}
}
}
if(flag == 1) {
break;
}
}
return new int[]{start, end};
}
}
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原文地址：http://www.cnblogs.com/wxisme/p/4604978.html
