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[leetcode] Convert Sorted List to Binary Search Tree

时间:2014-07-03 19:10:40      阅读:201      评论:0      收藏:0      [点我收藏+]

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Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.

https://oj.leetcode.com/problems/convert-sorted-list-to-binary-search-tree/

 

主要问题是链表中间节点不易获得。

思路1:链表转化成数组,然后上题做法。需要额外O(N)空间。

思路2:每次都从头找到中间节点,时间复杂度为O(NlogN)。

思路3:换一个思路,这次不top-down,而是bottom-up来做。一遍遍历链表,一遍中序遍历的顺序构建二叉树。

 

bubuko.com,布布扣
public class Solution {
    public TreeNode sortedListToBST(ListNode head) {
        int len = 0;
        ListNode p = head;
        while (p != null) {
            len++;
            p = p.next;
        }
        ListNode[] wrap = new ListNode[1];
        wrap[0] = head;
        return SLtoBST(wrap, 0, len);
    }

    private TreeNode SLtoBST(ListNode[] wrap, int start, int end) {
        if (start >= end)
            return null;
        int mid = start + (end - start) / 2;
        TreeNode left = SLtoBST(wrap, start, mid);
        TreeNode root = new TreeNode(wrap[0].val);
        root.left = left;
        wrap[0] = wrap[0].next;
        root.right = SLtoBST(wrap, mid + 1, end);
        return root;
    }

    public static void main(String[] args) {
        ListNode head = ListUtils.makeList(1);
        TreeNode root = new Solution().sortedListToBST(head);
    }

}
View Code

 

参考:

http://www.cnblogs.com/feiling/p/3267917.html

[leetcode] Convert Sorted List to Binary Search Tree,布布扣,bubuko.com

[leetcode] Convert Sorted List to Binary Search Tree

标签:style   blog   http   color   strong   os   

原文地址:http://www.cnblogs.com/jdflyfly/p/3821408.html

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