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Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.
也可使用set,hash
def contains_duplicate(nums) nums != nums.uniq end
数不太大的时候也可使用二进制操作方法，但在这题并不适用
bool containsDuplicate(int* nums, int numsSize) { int i = 0; int checker = 0; for (i=0;i<numsSize;i++){ if ((checker & (1 << nums[i])) > 0) return true; checker |= (1 << nums[i]); } return false; }
Leetcode 217 Contains Duplicate
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原文地址：http://www.cnblogs.com/lilixu/p/4609982.html
