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7
3 8
8 1 0
2 7 4 4
4 5 2 6 5
(Figure 1)
Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right.
5 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5
30
//从下往上推
#include<iostream>
#include<stdio.h>
using namespace std;
int main()
{
int n,i,j;
int a[100][100];
while(cin>>n)
{
for(i=0;i<n;i++)
for(j=0;j<=i;j++)
cin>>a[i][j];
for(i=n-2;i>=0;i--)
{
for(j=0;j<=i;j++)
{
a[i][j]+=a[i+1][j]>a[i+1][j+1]?a[i+1][j]:a[i+1][j+1];
}
}
cout<<a[0][0]<<endl;
}
return 0;
}版权声明:本文为博主原创文章,未经博主允许不得转载。
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原文地址:http://blog.csdn.net/phytn/article/details/46762181