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增广路以及残留网络的定义不再赘述了。算导上说的很清楚,证明也有,看懂了就知道怎么求最大流了。最后模板:
poj1273
#include<iostream>
#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<queue>
using namespace std;
const int maxn=250;
struct node{
int u,v,next,c;
};
node edge[maxn<<1];
int head[maxn];
int cnt;
int dis[maxn];
int n,m;
int ans;
void init(){
memset(head,-1,sizeof(head));
cnt=0;
memset(dis,-1,sizeof(dis));
ans=0;
}
void add(int a,int b,int c){
edge[cnt].u=a;
edge[cnt].v=b;
edge[cnt].c=c;
edge[cnt].next=head[a];
head[a]=cnt++;
}
int bfs()// 给各点分层,离源点的远近分
{
memset(dis, -1, sizeof(dis));
queue<int> q;
dis[1] = 0;
q.push(1);
int i;
int cur;
while(!q.empty())
{
cur = q.front();
q.pop();
for(i = head[cur]; i != -1; i = edge[i].next)
{
if(dis[edge[i].v] == -1 && edge[i].c > 0)
{
dis[edge[i].v] = dis[cur] + 1;
q.push(edge[i].v);
}
}
}
if(dis[m] < 0)
return 0;
return 1;
}
int Find(int x,int low){//找增广
int a;
if(x==m) return low;
for(int i=head[x];i!=-1;i=edge[i].next){
int v=edge[i].v;
if(dis[v]==dis[x]+1 && edge[i].c>0 &&(a=Find(v,min(low,edge[i].c))))
{
edge[i].c -=a;
edge[i^1].c +=a;
return a;
}
}
return 0;
}
void dinic(){
int temp;
while(bfs()){
// printf("%d\n",tmp);
// if(tmp==0) break;
temp=Find(1,0x3f3f3f3f);
ans+=temp;
}
printf("%d\n",ans);
}
int main(){
while(~scanf("%d%d",&n,&m)){
int a,b,flow;
init();
for(int i=1;i<=n;i++){
scanf("%d%d%d",&a,&b,&flow);
add(a,b,flow);
add(b,a,0);
}
dinic();
}
return 0;
}
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原文地址:http://blog.csdn.net/hitwhacmer1/article/details/47019789