标签:style blog http color os 2014
原题: ZOJ 3674 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3674
题意不难理解,很容易想到用暴力,但是无从下手,不知道怎么实现。后来看了网上的代码,直接用vector和map暴力,用到了set_intersection()函数,之前也听过这个函数,但是一直没写过,于是照着他的代码打了一遍,算是见识一下这个函数了。
代码看一下就能看懂了,关键看自己能不能写出来。
代码:
#include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <string> #include <vector> #include <map> #include <set> #include <cstdlib> using namespace std; #define N 10007 char name[35],ss[210],tips[210]; int check[110]; int main() { int n,m,i,j,a,b; int cword,ctips,ind,ccheck; while(scanf("%d",&n)!=EOF) { cword = ctips = 0; map<string,int> word; map<string,int> tip; map<int,string> atip; vector<int> G[110],K1,K2; for(j=1;j<=n;j++) { scanf("%s",name); if(!word[name]) word[name] = ++cword; //hash a = word[name]; getchar(); gets(ss); ind = 0; for(i=0;ss[i];i++) { if(ss[i] == ‘ ‘) { tips[ind] = ‘\0‘; if(!tip[tips]) { tip[tips] = ++ctips; atip[ctips] = tips; } b = tip[tips]; G[a].push_back(b); ind = 0; } else tips[ind++] = ss[i]; } tips[ind] = 0; if(!tip[tips]) { tip[tips] = ++ctips; atip[ctips] = tips; } b = tip[tips]; G[a].push_back(b); sort(G[a].begin(),G[a].end()); } scanf("%d",&m); getchar(); while(m--) { ccheck = 0; gets(ss); ind = 0; for(i=0;ss[i];i++) { if(ss[i] == ‘ ‘) { name[ind] = 0; check[ccheck++] = word[name]; ind = 0; } else name[ind++] = ss[i]; } name[ind] = 0; check[ccheck++] = word[name]; K1.clear(); vector<int> ::iterator it; for(it=G[check[0]].begin();it<G[check[0]].end();it++) K1.push_back(*it); for(i=1;i<ccheck;i++) { K2.clear(); set_intersection(K1.begin(),K1.end(),G[check[i]].begin(),G[check[i]].end(),back_inserter(K2)); i++; if(i >= ccheck) //last one { K1.clear(); for(it=K2.begin();it<K2.end();it++) K1.push_back(*it); break; } K1.clear(); set_intersection(K2.begin(),K2.end(),G[check[i]].begin(),G[check[i]].end(),back_inserter(K1)); } //最终结果看K1 if(!K1.size()) { puts("NO"); continue; } set<string> ans; for(it=K1.begin();it<K1.end();it++) ans.insert(atip[*it]); set<string>::iterator st; st = ans.begin(); cout<<*st; for(st++;st!=ans.end();st++) cout<<" "<<*st; puts(""); } } return 0; }
2014 Super Training #6 F Search in the Wiki --集合取交+暴力,布布扣,bubuko.com
2014 Super Training #6 F Search in the Wiki --集合取交+暴力
标签:style blog http color os 2014
原文地址:http://www.cnblogs.com/whatbeg/p/3830678.html