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Description
A ring is composed of n (even number) circles as shown in diagram. Put natural numbers
into each circle separately, and the sum of numbers in two adjacent circles should be a prime.
Note: the number of first circle should always be 1.
You are to write a program that completes above process.
6 8
Case 1: 1 4 3 2 5 6 1 6 5 2 3 4 Case 2: 1 2 3 8 5 6 7 4 1 2 5 8 3 4 7 6 1 4 7 6 5 8 3 2 1 6 7 4 3 8 5 2
#include<cstdio>
#include<algorithm>
using namespace std;
int S[20];
int main()
{
int n,casex=1;
long long ans,a;
while(scanf("%d",&n)!=EOF)
{
ans=0;
for(int i=1;i<=n;i++)
scanf("%d",&S[i]);
for(int i=1;i<=n;i++)
{
for(int j=i;j<=n;j++)
{
a=1;
for( int k=i;k<=j;k++)
{
a*=S[k];
}
ans=max(ans,a);
}
}
printf("Case #%d: The maximum product is %lld.\n\n",casex,ans);
casex++;
}
return 0;
}
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原文地址：http://blog.csdn.net/a1967919189/article/details/47090045
