标签:leetcode unique binary search
Unique Binary Search Trees II
Given n, generate all structurally unique BST‘s (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST‘s shown below.
1 3 3 2 1
\ / / / \ 3 2 1 1 3 2
/ / \ 2 1 2 3
迄今为止看到的最为经典的算法,分数超过14000的好评
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<TreeNode*> generateTrees(int n) {
return helper(1, n);
}
vector<TreeNode*> helper(int s, int e){
if(s>e){
return vector<TreeNode*>(1, NULL);
}
vector<TreeNode *> res;
for(int i=s; i<=e; i++){
vector<TreeNode *> left=helper(s, i-1);
vector<TreeNode *> right=helper(i+1, e);
for(int j=0; j<left.size(); j++){
for(int k=0; k<right.size(); k++){
TreeNode * p=new TreeNode(i);
p->left=left[j];
p->right=right[k];
res.push_back(p);
}
}
}
return res;
}
};来自leetcode:https://leetcode.com/discuss/26330/30-ms-c-solution版权声明:本文为博主原创文章,未经博主允许不得转载。
经典中的经典Unique Binary Search Trees II
标签:leetcode unique binary search
原文地址:http://blog.csdn.net/jisuanji_wjfioj/article/details/47133393