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题目：
Given an array of integers, every element appears twice except for one. Find that single one.
解法一： bit manipulate
1 public class Solution { 2 public int singleNumber(int[] nums) { 3 int ans = 0; 4 for (int i = 0; i < nums.length; i++) ans ^= nums[i]; 5 return ans; 6 7 8 } 9 }
解法二：hash table ->不是太明白！！
1 public int singleNumber(int[] A) { 2 HashSet<Integer> set = new HashSet<Integer>(); 3 for (int n : A) { 4 if (!set.add(n)) 5 set.remove(n); 6 } 7 Iterator<Integer> it = set.iterator(); 8 return it.next(); 9 }
reference：
http://blog.csdn.net/kenden23/article/details/13625297
http://www.programcreek.com/2012/12/leetcode-solution-of-single-number-in-java/
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原文地址：http://www.cnblogs.com/hygeia/p/4687851.html
