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Description
Input
Output
Sample Input
100 7 1 101 1 2 1 2 2 2 3 2 3 3 1 1 3 2 3 1 1 5 5
Sample Output
3
关系性并查集;
#include<cstdio>
#include<cstring>
using namespace std;
int n,d,sum;
int father[50010],relx[50010];
int find(int x)
{
int rx;
if (x!=father[x])
{
rx=find(father[x]);
relx[x]=(relx[x]+relx[father[x]])%3;
father[x]=rx;
}
return father[x];
}
int un(int x,int y)
{
int rx=find(x),ry=find(y);
if (rx==ry)
{
if ((relx[y]-relx[x]+3)%3==d-1) return 0;
return 1;
}
father[ry]=rx;
relx[ry]=(relx[x]-relx[y]+d+2)%3;
return 0;
}
int main()
{
int k,x,y,i;
sum=0;
scanf("%d%d",&n,&k);
for (i=1;i<=n;i++) {father[i]=i;relx[i]=0;}
while (k--)
{
scanf("%d%d%d",&d,&x,&y);
if (x>n||y>n||(x==y&&d==2)) {sum++;continue;}
if (un(x,y)==1) sum++;
}
printf("%d\n",sum);
}
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原文地址:http://www.cnblogs.com/pblr/p/4692468.html