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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 14177 Accepted Submission(s): 4049

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
#define N 100005
long long dpl[N],dpr[N],hei[N],maxn,t;
int main()
{
int n;
while(scanf("%d",&n)!=EOF&&n)
{
maxn=0;
for(int i=1;i<=n;i++)
scanf("%I64d",&hei[i]);
dpl[1]=1;
dpr[n]=n;
for(int i=2;i<=n;i++) //找当前矩形左边能延伸到的矩形,第几个,下标
{
t=i;
while(t>1&&hei[i]<=hei[t-1])
t=dpl[t-1];
dpl[i]=t;
}
for(int i=n-1;i;i--) //找当前矩形右边能够延伸到的矩形,第几个,下标
{
t=i;
while(t<n&&hei[i]<=hei[t+1])
t=dpr[t+1];
dpr[i]=t;
}
for(int i=1;i<=n;i++)
{
long long tot=(dpr[i]-dpl[i]+1)*hei[i];
if(tot>maxn)
maxn=tot;
}
cout<<maxn<<endl;
}
return 0;
}
HDU_1506_Largest Rectangle in a Histogram_dp
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原文地址:http://www.cnblogs.com/jasonlixuetao/p/4707606.html