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leecode Contains Duplicate

时间:2015-08-14 00:57:36      阅读:99      评论:0      收藏:0      [点我收藏+]

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Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.

 

class Solution:
    # @param {integer[]} nums
    # @return {boolean}
    def containsDuplicate(self, nums):
        if len(nums) <= 0:
            return False
        arrCheck = {}
        for i in nums:
            if arrCheck.has_key( i ):
                return True
            arrCheck[i] = i
        return False

 

leecode Contains Duplicate

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原文地址:http://www.cnblogs.com/allenhaozi/p/4728805.html

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