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1 1 0 3 7
题意:给n个母串,给m个匹配串,求每个母串依次和匹配串匹配,能得到的数目和。
题解:AC自动机模板题
#include <stdio.h>
#include <algorithm>
#include <iostream>
#include <string.h>
#include <queue>
using namespace std;
struct Trie {
int next[500010][26],fail[500010],end[500010];
int root,L;
int newnode() {
for(int i = 0; i < 26; i++)
next[L][i] = -1;
end[L++] = 0;
return L-1;
}
void init() {
L = 0;
root = newnode();
}
void insert(char buf[]) {
int len = strlen(buf);
int now = root;
for(int i = 0; i < len; i++) {
if(next[now][buf[i]-'a'] == -1)
next[now][buf[i]-'a'] = newnode();
now = next[now][buf[i]-'a'];
}
end[now]++;
}
void build() {
queue<int>Q;
fail[root] = root;
for(int i = 0; i < 26; i++)
if(next[root][i] == -1)
next[root][i] = root;
else {
fail[next[root][i]] = root;
Q.push(next[root][i]);
}
while( !Q.empty() ) {
int now = Q.front();
Q.pop();
for(int i = 0; i < 26; i++)
if(next[now][i] == -1)
next[now][i] = next[fail[now]][i];
else {
fail[next[now][i]]=next[fail[now]][i];
Q.push(next[now][i]);
}
}
}
int query(char buf[]) {
int len = strlen(buf);
int now = root;
int res = 0;
for(int i = 0; i < len; i++) {
now = next[now][buf[i]-'a'];
int temp = now;
while( temp != root ) {
res += end[temp];
//end[temp] = 0;
temp = fail[temp];
}
}
return res;
}
void debug() {
for(int i = 0; i < L; i++) {
printf("id = %3d,fail = %3d,end = %3d,chi = [",i,fail[i],end[i]);
for(int j = 0; j < 26; j++)
printf("%2d",next[i][j]);
printf("]\n");
}
}
};
char buf[100010];
int m;
char s[605015];
char c[10010];
Trie ac;
int main() {
// freopen("test.in","r",stdin);
int T;
int n;
scanf("%d",&T);
while( T-- ) {
scanf("%d%d",&n,&m);
ac.init();
memset(s,0,sizeof s);
int len=0;
for(int i=0; i<n; i++) { ///把所有的串接起来,用空格隔开
scanf("%s",c);
int l=strlen(c);
if(i!=0)s[len++]=' ';
strcat(s,c);
len+=l;
}
s[len]=' ';
s[++len]=0;
for(int i=0; i<m; i++) {
scanf("%s",buf);
ac.insert(buf);
}
ac.build();
int l=0;
while(l<len) {
int k=0;
while(s[l]!=' ') {///找到当前单词
buf[k++]=s[l++];
}
buf[k]=0;
l++;
printf("%d\n",ac.query(buf));
}
}
return 0;
}
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原文地址:http://blog.csdn.net/acm_baihuzi/article/details/47674317