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Determine the number of bits required to flip if you want to convert integer n to integer m.
Given n = 31 (11111), m = 14 (01110), return 2.
Both n and m are 32-bit integers.
Normal Solution:
class Solution { public: /** *@param a, b: Two integer *return: An integer */ int bitSwapRequired(int a, int b) { // write your code here int cnt = 0; for(int i = 0;i < 32;i++){ if((a&1) != (b&1)) cnt++; a >>= 1; b >>= 1; } return cnt; } };
Use STL:
#include <bitset> class Solution { public: /** *@param a, b: Two integer *return: An integer */ int bitSwapRequired(int a, int b) { // write your code here bitset<32> bitvec_a(a), bitvec_b(b); int cnt = 0; for(int i = 0;i < 32;i++) if(bitvec_a[i] != bitvec_b[i]) cnt++; return cnt; } };
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原文地址：http://www.cnblogs.com/changchengxiao/p/4731873.html
