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[LeetCode]Happy Number

时间:2015-08-17 16:51:59      阅读:113      评论:0      收藏:0      [点我收藏+]

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Happy Number

Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

  • 12 + 92 = 82
  • 82 + 22 = 68
  • 62 + 82 = 100
  • 12 + 02 + 02 = 1

 

问题在于判断是否进入循环,可以用Hash table记录出现过的数字,当再次出现,则进入循环。和Fraction to Recurring Decimal问题类似。

 1 class Solution {
 2 public:
 3     bool isHappy(int n) {
 4         unordered_set<int> showed;
 5         if(n<1)
 6         {
 7             return false;
 8         }
 9         if(n==1)
10         {
11             return true;
12         }
13         int s;
14         while(true)
15         {
16             s=0;
17             while(n!=0)
18             {
19                 s+=(n%10)*(n%10);
20                 n/=10;
21             }
22             if(s==1)
23             {
24                 return true;
25             }
26             else if(showed.find(s)!=showed.end())
27             {
28                 return false;
29             }
30             showed.insert(s);
31             n=s;
32         }
33     }
34 };

 

[LeetCode]Happy Number

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原文地址:http://www.cnblogs.com/Sean-le/p/4736820.html

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