标签:des style blog class code ext
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 5684 | Accepted: 2894 |
Description
Input
Output
Sample Input
4 6 4 3 2 2 1 1 5 3 2 1 1 400 12 50 50 50 50 50 50 25 25 25 25 25 25 0 0
Sample Output
Sums of 4: 4 3+1 2+2 2+1+1 Sums of 5: NONE Sums of 400: 50+50+50+50+50+50+25+25+25+25 50+50+50+50+50+25+25+25+25+25+25
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#include <iostream>#include <cstdio>#include <cstring>#include <cstdlib>#include <algorithm>using
namespace std;const
int maxn=10+5;int
a[maxn],cur[maxn];int
ok,sum,n;inline
void DFS(int
index,int
cursum,int
cnt){ if(cursum==0) { ok=0; printf("%d",cur[0]); for(int
i=1;i<cnt;i++) { printf("+%d",cur[i]); } printf("\n"); return
; } else { for(int
i=index;i<n;i++) { if(i==index||a[i]!=a[i-1]) //注意去重,如果当前这个数是这一层的第一个,一定要,如果不是第一个,并且和前一个相同,就不用考虑 { //因为如果与前面一个相同,就相当于当前这个串是前面的一个子串 cur[cnt]=a[i]; DFS(i+1,cursum-a[i],cnt+1); } } } return
;}int
main(){ while(scanf("%d%d",&sum,&n)!=EOF&&n!=0) { memset(cur,0,sizeof(cur)); memset(a,0,sizeof(a)); for(int
i=0;i<n;i++) scanf("%d",&a[i]); ok=1; printf("Sums of %d:\n",sum); DFS(0,sum,0); if(ok) printf("NONE\n"); } return
0;} |
标签:des style blog class code ext
原文地址:http://www.cnblogs.com/scottding/p/3712977.html