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Single Number i,ii,iii

时间:2016-12-01 14:10:00      阅读:215      评论:0      收藏:0      [点我收藏+]

标签:val   code   which   add   rem   remove   find   default   tor   

136. Single Number

Given an array of integers, every element appears twice except for one. Find that single one.

Bit: a ^ a = 0;

public class Solution {
    public int singleNumber(int[] nums) {
        int res = 0;
        for(int n : nums){
            res ^= n;
        }
        return res;
    }
}

 

137. Single Number II

public class Solution {
    public int singleNumber(int[] nums) {
        HashMap<Integer, Integer> map = new HashMap<>();
        for(int i = 0 ; i < nums.length ; i++){
            map.put(nums[i], map.getOrDefault(nums[i], 0) + 1);
        }
        for(Map.Entry<Integer, Integer> entry : map.entrySet()){
            if(entry.getValue() == 1)
                return entry.getKey();
        }
        return 0;
    }
}

 

260. Single Number III

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once.

For example:

Given nums = [1, 2, 1, 3, 2, 5], return [3, 5].

public class Solution {
    public int[] singleNumber(int[] nums) {
        Set<Integer> set = new HashSet<>();
        for(int n: nums){
            if(!set.add(n)){
                set.remove(n);
            }
        }
        Iterator<Integer> it = set.iterator();
        int[] res = new int[2];
        int start = 0;
        while(it.hasNext() && start < res.length){
            res[start] = it.next();
            start++;
        }
        return res;
    }
}

 

二刷可以研究bit做法

Single Number i,ii,iii

标签:val   code   which   add   rem   remove   find   default   tor   

原文地址:http://www.cnblogs.com/joannacode/p/6121399.html

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