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【Leetcode】Remove Element

时间:2014-08-20 13:59:22      阅读:176      评论:0      收藏:0      [点我收藏+]

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Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn‘t matter what you leave beyond the new length. 

 

1st (2 tries)

class Solution 
{
public:
    int removeElement(int A[], int n, int elem) 
    {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        int i,j;
        for(i = 0;i < n;++i)
        {
            if(A[i] == elem)
            {
                for(j = i+1;j < n;++j)
                {
                    A[j-1] = A[j];
                }
                --n;
                --i;
            }
        }
        return n;
    }
};

  

2nd(2 tries)

class Solution {
public:
    int removeElement(int A[], int n, int elem) {
        //swap to the end;
        int start = 0,end = n-1;
        for(int i = start;i <= end;i++) {
            if(A[i] == elem) {
                swap(A[i--],A[end--]);
            }
        }
        return end - start + 1;
    }
};

  

【Leetcode】Remove Element,布布扣,bubuko.com

【Leetcode】Remove Element

标签:blog   io   for   ar   art   cti   div   log   

原文地址:http://www.cnblogs.com/weixliu/p/3924353.html

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