码迷,mamicode.com
首页 > 其他好文 > 详细

eg_1

时间:2017-04-24 21:14:06      阅读:167      评论:0      收藏:0      [点我收藏+]

标签:print   sys   case   div   class   rac   har   log   char   

1. 编写一个程序,输出一个字符串中的大写英文字母个数,小写英文字母个数以及非英文字母个数.

  第一种方法:

public class Test {
	public static void main(String[] args) {
		String s = "AaabbcceeeFgFhjklOIU9890454jiaQQqwq_!!!@09&&&haAA";
		int Lcount = 0, Ucount = 0, Ocount = 0;
		for(int i=0;i<s.length();i++){
			if(s.charAt(i) >= ‘a‘ && s.charAt(i) <= ‘z‘){
				Lcount++;
			}
			else if(s.charAt(i) >= ‘A‘ && s.charAt(i) <= ‘Z‘){
				Ucount++;
			}
			else {
				Ocount++;
			}
		}
		System.out.println("Lcount: "+Lcount+","+"Ucount: "+Ucount+","+"Ocount: "+Ocount);
	}
} //Lcount: 22,Ucount: 10,Ocount: 17

  第二种方法:

public class Test {
	public static void main(String[] args) {
		String s = "AaabbcceeeFgFhjklOIU9890454jiaQQqwq_!!!@09&&&haAA";
		int Lcount = 0, Ucount = 0, Ocount = 0;
		for(int i=0;i<s.length();i++){
			if(Character.isLowerCase(s.charAt(i))){
				Lcount++;
			}
			else if(Character.isUpperCase(s.charAt(i))){
				Ucount++;
			}
			else {
				Ocount++;
			}
		}
		System.out.println("Lcount: "+Lcount+","+"Ucount: "+Ucount+","+"Ocount: "+Ocount);
	}
}// Lcount: 22,Ucount: 10,Ocount: 17

 第三种方法:

public class Test {
	public static void main(String[] args) {
		String BL = "abcdefghijklmnopqrstuvwxyz";
		String BU = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
		String s = "AaabbcceeeFgFhjklOIU9890454jiaQQqwq_!!!@09&&&haAA";
		int Lcount = 0, Ucount = 0, Ocount = 0;
		for(int i=0;i<s.length();i++){
			if(BL.indexOf(s.charAt(i)) != -1){
				Lcount++;
			}
			else if(BU.indexOf(s.charAt(i)) != -1){
				Ucount++;
			}
			else {
				Ocount++;
			}
		}
		System.out.println("Lcount: "+Lcount+","+"Ucount: "+Ucount+","+"Ocount: "+Ocount);
	}
}// Lcount: 22,Ucount: 10,Ocount: 17

 

eg_1

标签:print   sys   case   div   class   rac   har   log   char   

原文地址:http://www.cnblogs.com/bosongokay/p/6758906.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!