标签:operator oid queue 最短路 ble line .com logs bsp
dis[i][j]表示第i个点,更新了j次的最短路
此题不良心,卡spfa
#include <queue>
#include <cstdio>
#include <cstring>
#include <iostream>
#define N 50001
using namespace std;
struct node
{
int a, b, c;
node(int a, int b, int c) : a(a), b(b), c(c) {}
bool operator > (const node& gg) const
{
return a > gg.a;
}
};
int n, m, k, cnt;
int head[N], to[N << 1], next[N << 1], val[N << 1], dis[N][21];
bool vis[N][21];
priority_queue <node, vector <node>, greater <node> > q;
inline int read()
{
int x = 0, f = 1;
char ch = getchar();
for(; !isdigit(ch); ch = getchar()) if(ch == ‘-‘) f = -1;
for(; isdigit(ch); ch = getchar()) x = (x << 1) + (x << 3) + ch - ‘0‘;
return x * f;
}
inline void add(int x, int y, int z)
{
to[cnt] = y;
val[cnt] = z;
next[cnt] = head[x];
head[x] = cnt++;
}
inline void dijkstra()
{
int i, u, v, x;
memset(dis, 127, sizeof(dis));
q.push(node(0, 1, 0));
dis[1][0] = 0;
while(!q.empty())
{
u = q.top().b;
x = q.top().c;
q.pop();
if(vis[u][x]) continue;
vis[u][x] = 1;
for(i = head[u]; i ^ -1; i = next[i])
{
v = to[i];
if(dis[v][x] > dis[u][x] + val[i])
{
dis[v][x] = dis[u][x] + val[i];
q.push(node(dis[v][x], v, x));
}
if(x + 1 <= k && dis[v][x + 1] > dis[u][x])
{
dis[v][x + 1] = dis[u][x];
q.push(node(dis[v][x + 1], v, x + 1));
}
}
}
}
int main()
{
int i, x, y, z;
n = read();
m = read();
k = read();
memset(head, -1, sizeof(head));
for(i = 1; i <= m; i++)
{
x = read();
y = read();
z = read();
add(x, y, z);
add(y, x, z);
}
dijkstra();
printf("%d\n", dis[n][k]);
return 0;
}
[BZOJ1579] [Usaco2009 Feb]Revamping Trails 道路升级(分层图最短路 + 堆优化dijk)
标签:operator oid queue 最短路 ble line .com logs bsp
原文地址:http://www.cnblogs.com/zhenghaotian/p/7511923.html