标签：amp check cti form dfs class orm round 上下
Given a 2d grid map of ‘1‘s (land) and ‘0‘s (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.
Example 1:
11110
11010
11000
00000
Answer: 1
Example 2:
11000
11000
00100
00011
Answer: 3
思路 = dfs（四叉树，上下左右） +剪枝
剪枝是剪掉遍历过的结点
class Solution(object):
def numIslands(self, grid):
"""
:type grid: List[List[str]]
:rtype: int
"""
count=0
m=len(grid)
if m==0:
return 0
n=len(grid[0])
#visit=[[False]*n]*m
visit = [[False for i in range(n)]for j in range(m)]
def check(x, y):
if x >= 0 and x<m and y>= 0 and y< n and grid[x][y] == ‘1‘ and visit[x][y] == False:
return True
def dfs(i ,j):
nbrow = [1,0,-1,0]
nbcol = [0,1,0,-1]
for d in range(4):
ni=i+nbrow[d]
nj=j+nbcol[d]
if(check(ni,nj)==True):
visit[ni][nj]=True
dfs(ni,nj)
for i in range(m):
for j in range(n):
if(check(i,j)==True):
visit[i][j]=True
dfs(i,j)
count+=1
return count
python 学习 leetcode ---number of island
标签：amp check cti form dfs class orm round 上下
原文地址：http://www.cnblogs.com/fanhaha/p/7846788.html
