标签:efi 第四次 ret float 结构体 include png turn class
题目6-1 计算两数的和与差
1.设计思路
(1)第一步:读懂题目
第二步:编写程序
(2):流程图
2.实验代码
#include <stdio.h>
#define MAXN 10
struct student{
int num;
char name[20];
int score;
char grade;
};
int set_grade( struct student *p, int n );
int main()
{ struct student stu[MAXN], *ptr;
int n, i, count;
ptr = stu;
scanf("%d\n", &n);
for(i = 0; i < n; i++){
scanf("%d%s%d", &stu[i].num, stu[i].name, &stu[i].score);
}
count = set_grade(ptr, n);
printf("The count for failed (<60): %d\n", count);
printf("The grades:\n");
for(i = 0; i < n; i++)
printf("%d %s %c\n", stu[i].num, stu[i].name, stu[i].grade);
return 0;
}
int set_grade( struct student *p, int n ){
int count = 0, i;
for(i = 0;i<n;i++,p++){
if(p->score<60){
p->grade = ‘D‘;
count++;
}
else if((p->score<70)&&(p->score>=60)){
p->grade = ‘C‘;
}
else if((p->score<85)&&(p->score>=70)){
p->grade = ‘B‘;
}
else{
p->grade = ‘A‘;
}
}
return count;
}
3

6-2 结构体数组按总分排序
1.设计思路
(1)第一步:读懂题目
第二步:编写程序
(2)流程图
略
2.实验代码
#include <stdio.h>
struct student
{
int num;
char name[15];
float score[3];
float sum;
};
void calc(struct student *p,int n);
void sort(struct student *p,int n);
int main()
{
struct student stu[5];
int i,j;
float f;
for(i=0;i<5;i++)
{
scanf("%d%s",&stu[i].num,stu[i].name);
for(j=0;j<3;j++)
{
scanf("%f",&f);
stu[i].score[j]=f;
}
}
calc(stu,5);
sort(stu,5);
for(i=0;i<5;i++)
{
printf("%5d%15s",stu[i].num,stu[i].name);
printf(" %.1f %.1f %.1f %.1f\n",stu[i].score[0],stu[i].score[1],stu[i].score[2], stu[i].sum);
}
return 0;
void calc(struct student *p,int n)
{
int i;
for(i=0;i<n;i++,p++)
{
p->sum = p->score[0]+p->score[1]+p->score[2];
}
}
void sort(struct student *p,int n)
{
int i=0,j=0;
struct student t;
for(i=0;i<n;i++)
{
for(j=0;j<n-1;j++)
{
if(p[j].sum < p[j+1].sum)
{
t = p[j];
p[j] = p[j+1];
p[j+1] = t;
}
}
}
}
3.本题调试过程中遇到的问题及解决方法:
无

标签:efi 第四次 ret float 结构体 include png turn class
原文地址:https://www.cnblogs.com/abc12345/p/8892995.html