标签：list code res lse pre class [] his amp
Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once.
Find all the elements of [1, n] inclusive that do not appear in this array.
Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space.
Example:
Input: [4,3,2,7,8,2,3,1] Output: [5,6]
class Solution { public List<Integer> findDisappearedNumbers(int[] nums) { // put all nums in correct place. nums[nums[i] - 1] = nums[i] for (int i = 0; i < nums.length;) { int newIndex = nums[i] - 1; if (i != newIndex && nums[i] != i + 1 && nums[i] != nums[newIndex]) { int temp = nums[newIndex]; nums[newIndex] = nums[i]; nums[i] = temp; } else { i++; } } // count the missing numbers List<Integer> result = new ArrayList<>(); for (int i = 0; i < nums.length; i++) { if (nums[i] != i + 1) { result.add(i + 1); } } return result; } }
Find All Numbers Disappeared in an Array
标签：list code res lse pre class [] his amp
原文地址：https://www.cnblogs.com/amazingzoe/p/9062361.html
