Leetcode 13 罗马数字转整数

def Rome(x):
    dict={
        ‘I‘:1,
        ‘V‘:5,
        ‘X‘:10,
        ‘L‘:50,
        ‘C‘:100,
        ‘D‘:500,
        ‘M‘:1000
    }
    z=list(x)
    print(z)
    sum=0
    for i in z:
        sum=sum+dict[i]
    if ‘IV‘ in x or ‘IX‘in x:
        num = x.count(‘IV‘)+x.count(‘IX‘)
        sum = sum - num * 2
    if ‘XL‘ in x or ‘XC‘in x:
        num=x.count(‘XL‘)+x.count(‘XC‘)
        sum=sum-num*20
    if ‘CD‘ in x or ‘CM‘in x:
        num=x.count(‘CD‘)+x.count(‘CM‘)
        sum=sum-num*200
    return sum