标签:open const return printf can using val operator freopen
Code:
// luogu-judger-enable-o2
// luogu-judger-enable-o2
#include <bits/stdc++.h>
#define setIO(s) freopen(s".in","r",stdin)
#define maxn 1000000
#define inf 0x7f7f7f
using namespace std;
int hd[maxn],to[maxn],nex[maxn],val[maxn],f[maxn],vis[maxn],siz[maxn],dep[maxn],ans,cur=0;
int cnt,n,k,root,sn,d[2];
void addedge(int u,int v,int c)
{
nex[++cnt] = hd[u],hd[u] = cnt,to[cnt] = v,val[cnt] = c;
}
struct Point{
int dis,tot;
Point(int dis = 0,int tot = 0):dis(dis),tot(tot){}
bool operator<(Point b)const{
return b.dis != dis ? b.dis>dis : b.tot > tot;
}
}point[2][maxn];
void getdis(int u,int fa,int tot)
{
point[cur][++d[cur]]=Point(dep[u],tot);
for(int i = hd[u]; i ; i = nex[i])
{
if(vis[to[i]] || to[i] == fa) continue;
dep[to[i]] = dep[u] + val[i],getdis(to[i],u,tot + 1);
}
}
void GetRoot(int u,int ff)
{
siz[u] = 1,f[u] = 0;
for(int i = hd[u]; i ; i = nex[i])
{
if(vis[to[i]] || to[i] == ff) continue;
GetRoot(to[i],u);
siz[u] += siz[to[i]];
f[u] = max(f[u], siz[to[i]]);
}
f[u] = max(f[u], sn - siz[u]);
if(f[u] < f[root]) root = u;
}
void DFS(int u)
{
vis[u] = 1, dep[u] = 0, cur = 0, d[cur] = 0,d[cur^1] = 1,point[cur^1][1] = Point(0,0);
for(int i = hd[u]; i ; i = nex[i])
{
if(vis[to[i]]) continue;
dep[to[i]] = val[i];
d[cur] = 0;
root = 0,sn = siz[to[i]],GetRoot(to[i],u), DFS(root);
getdis(to[i],0,1);
sort(point[cur]+1,point[cur]+1+d[cur]);
int m = 1;
for(int j = 2;j <= d[cur]; ++j) if(point[cur][j].dis!=point[cur][j-1].dis) point[cur][++m]=point[cur][j];
d[cur] = m;
int p1 = 1,p2 = d[cur^1];
while(p1 <= d[cur] && p2 >=1)
{
if(point[cur][p1].dis + point[cur^1][p2].dis == k) ans = min(ans,point[cur][p1].tot + point[cur^1][p2].tot), ++p1,--p2;
if(point[cur][p1].dis + point[cur^1][p2].dis < k) ++p1;
if(point[cur][p1].dis + point[cur^1][p2].dis > k) --p2;
}
for(int j = 1;j <= d[cur]; ++j) point[cur^1][++d[cur^1]] = point[cur][j];
sort(point[cur^1]+1,point[cur^1]+1+d[cur^1]);
m = 1;
for(int j=2;j<=d[cur^1];++j) if(point[cur^1][j].dis!=point[cur^1][j-1].dis)point[cur^1][++m]=point[cur^1][j];
d[cur^1]=m, d[cur]=0;
}
}
int main()
{
setIO("input");
scanf("%d%d",&n,&k);
for(int i = 1,a,b,c;i < n; ++i) scanf("%d%d%d",&a,&b,&c),addedge(a+1,b+1,c),addedge(b+1,a+1,c);
ans = inf, vis[0] = 1,f[0] = inf,sn = n,root = 0, GetRoot(1,0),DFS(root);
printf("%d\n",ans==inf?-1:ans);
return 0;
}
bzoj 2599 [IOI2011]Race 未调完_点分治
标签:open const return printf can using val operator freopen
原文地址:https://www.cnblogs.com/guangheli/p/10939790.html