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Squares of a Sorted Array

时间:2019-07-19 14:04:51      阅读:100      评论:0      收藏:0      [点我收藏+]

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Given an array of integers A sorted in non-decreasing order, return an array of the squares of each number, also in sorted non-decreasing order. 

Example 1:

Input: [-4,-1,0,3,10]
Output: [0,1,9,16,100]

Example 2:

Input: [-7,-3,2,3,11]
Output: [4,9,9,49,121]

 1 class Solution {
 2     public int[] sortedSquares(int[] A) {
 3         int n = A.length;
 4         int[] result = new int[n];
 5         int i = 0, j = n - 1;
 6         for (int p = n - 1; p >= 0; p--) {
 7             if (Math.abs(A[i]) > Math.abs(A[j])) {
 8                 result[p] = A[i] * A[i];
 9                 i++;
10             } else {
11                 result[p] = A[j] * A[j];
12                 j--;
13             }
14         }
15         return result;
16     }
17 }

 

 

Squares of a Sorted Array

标签:class   ++   result   style   span   return   color   turn   bsp   

原文地址:https://www.cnblogs.com/beiyeqingteng/p/11212808.html

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