POJ训练计划1936_All in All(串处理)

You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string. 

Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove characters from t such that the concatenation of the remaining characters is s. 

The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by whitespace.The length of s and t will no more than 100000.

For each test case output "Yes", if s is a subsequence of t,otherwise output "No".

sequence subsequence
person compression
VERDI vivaVittorioEmanueleReDiItalia
caseDoesMatter CaseDoesMatter

Yes
No
Yes
No

Ulm Local 2002

解题报告

水一题。。。

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>

using namespace std;

int main()
{
    int i,j;
    char str1[100010],str2[100010];
    while(cin>>str1>>str2)
    {
        int m=0;
        int l1=strlen(str1);
        int l2=strlen(str2);
        for(i=0;i<l2;i++)
        {
            if(str2[i]==str1[m])
                m++;
            if(m==l1)
                break;
        }
        if(m==l1)cout<<"Yes"<<endl;
        else cout<<"No"<<endl;
    }
    return 0;
}