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Leetcode Binary Tree Preorder Traversal

时间:2014-06-21 06:40:07      阅读:172      评论:0      收藏:0      [点我收藏+]

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Given a binary tree, return the preorder traversal of its nodes‘ values.

For example:
Given binary tree {1,#,2,3},

   1
         2
    /
   3

 

return [1,2,3].

Note: Recursive solution is trivial, could you do it iteratively?

本题是非递归先序遍历二叉树,任何一本数据结构书上都有

vector<int> preorderTraversal(TreeNode * root){
    vector<int> res;
    if(root == NULL) return res;
    stack<TreeNode *> record;
    record.push(root);
    while(!record.empty()){
        TreeNode *node = record.top();
        record.pop();
        res.push_back(node->val);
        if(node->right) record.push(node->right);
        if(node->left) record.push(node->left);
    }    
    return res;
}

 

 

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Leetcode Binary Tree Preorder Traversal

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原文地址:http://www.cnblogs.com/xiongqiangcs/p/3795492.html

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